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Pushing the current branch has three cases: it has an upstream, it has none but push.default is "current", or the user is prompted for one. Each case ends in a push, and the first one also checks whether a force push is needed. Let the three cases call a common callback instead, and put the check and the push there. This makes it possible to run the same three cases with a different callback, so that the branches stacked below the current one can be pushed along with it. The check returns false for a branch without an upstream, so the other two cases behave as before. Co-Authored-By: Claude Fable 5.1 <noreply@anthropic.com>